A wave moving with constant speed on a uniform string passes the point x = 0 with amplitude A 0 , angular frequency ꞷ 0 and average rate of energy transfer P0. As the wave travels down the string it gradually loses energy and at the point x = λ , the average rate of energy transfer becomes 
. At the point x = λ , angular frequency and amplitude are respectively:
A
ꞷ 0 and A 0 / 
B
ꞷ 0 / 
and A 0
and A 0
C
less than ꞷ 0 and A 0
D
ꞷ 0 / 
and A 0 / 
and A 0 /
Text Solution
Verified by ExpertsThe correct answer is:
A
p 0 = A 0 2 ꞷ 0 2 µv
= A 2 ꞷ 2 µv
∴ 2 = 
∴ As,ꞷ = ꞷ 0 (frequency remains the same)
∴ A = 
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